What is ((-10x^3+30x-20))/((-5x+5)) ?

The solution to ((-10x^3+30x-20))/((-5x+5)) is 2(x-1)(x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((-10x^3+30x-20))/((-5x+5))

simplify

\frac{( - 10 x ^{3} + 30 x - 20 )}{( - 5 x + 5 )}

2 (x - 1) (x + 2)

Solution steps

\frac{- 10 x ^{3} + 30 x - 20}{- 5 x + 5}

Factor

- 10 x^{3} + 30 x - 20 : - 10 (x - 1)^{2} (x + 2)

= \frac{- 10 ( x - 1 ) ^{2} ( x + 2 )}{- 5 x + 5}

Factor

- 5 x + 5 : 5 (- x + 1)

= \frac{- 10 ( x - 1 ) ^{2} ( x + 2 )}{5 ( - x + 1 )}

Factor the number:

10 = 5 \cdot 2

= \frac{- 5 \cdot 2 ( x - 1 ) ^{2} ( x + 2 )}{5 ( - x + 1 )}

Cancel the common factor:

5

= \frac{- 2 ( x - 1 ) ^{2} ( x + 2 )}{- x + 1}

Factor

- x + 1 : - (x - 1)

= \frac{- 2 ( x - 1 ) ^{2} ( x + 2 )}{- ( x - 1 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x - 1)^{2} = (x - 1) (x - 1)

= \frac{- 2 ( x - 1 ) ( x - 1 ) ( x + 2 )}{- ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{- 2 ( x - 1 ) ( x + 2 )}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2 ( x - 1 ) ( x + 2 )}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 2 (x - 1) (x + 2)

6.75

20 \cdot 1 0^{- 3}

(x a + a x)^{2}

(3 - 5 i) + (7 + 3 i)

\frac{6}{8 a + 4} + \frac{3 a}{8}

What is ((-10x^3+30x-20))/((-5x+5)) ?
The solution to ((-10x^3+30x-20))/((-5x+5)) is 2(x-1)(x+2)