What is (3+i)-(4-3i) ?

The solution to (3+i)-(4-3i) is -1+4i

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simplify (3+i)-(4-3i)

simplify

(3 + i) - (4 - 3 i)

- 1 + 4 i

Solution steps

(3 + i) - (4 - 3 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (3 - 4) + (1 - (- 3)) i

Simplify

(3 - 4) + (1 - (- 3)) i : - 1 + 4 i

= - 1 + 4 i

\frac{2}{8} \div \frac{3}{4} \div \frac{6}{5}

cot (θ) - cot (θ) cos^{2} (θ)

(2 x^{2})^{- 3}

(- 1 + x)^{3}

\frac{1 - 3}{3}