What is 1/(x+3)+1/(x^2-9) ?

The solution to 1/(x+3)+1/(x^2-9) is (x-2)/((x+3)(x-3))

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simplify 1/(x+3)+1/(x^2-9)

simplify

\frac{1}{x + 3} + \frac{1}{x ^{2} - 9}

\frac{x - 2}{( x + 3 ) ( x - 3 )}

Solution steps

\frac{1}{x + 3} + \frac{1}{x ^{2} - 9}

Least Common Multiplier of

x + 3, x^{2} - 9 : (x + 3) (x - 3)

Adjust Fractions based on the LCM

= \frac{x - 3}{( x + 3 ) ( x - 3 )} + \frac{1}{( x + 3 ) ( x - 3 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{x - 3 + 1}{( x + 3 ) ( x - 3 )}

Add the numbers:

- 3 + 1 = - 2

= \frac{x - 2}{( x + 3 ) ( x - 3 )}

\frac{8}{3 x ^{2}} + \frac{5}{4 x}

\frac{40 - 50}{\frac{8}{25}}

\frac{80}{12}

(1 - cos^{2} (x))^{3}

(- 2 a^{2} b)^{2} (- 3 ab)^{3} (a b^{2})^{4}

What is 1/(x+3)+1/(x^2-9) ?
The solution to 1/(x+3)+1/(x^2-9) is (x-2)/((x+3)(x-3))