What is x^6-x^4+2x^3-6x^2+4x>= 0 ?

The solution to x^6-x^4+2x^3-6x^2+4x>= 0 is x = 0

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x^6-x^4+2x^3-6x^2+4x>= 0

x^{6} - x^{4} + 2 x^{3} - 6 x^{2} + 4 x \geq 0

x \leq - 2 or x \geq 0

Interval Notation

(- \infty, - 2] \cup [0, \infty)

Solution steps

x^{6} - x^{4} + 2 x^{3} - 6 x^{2} + 4 x \geq 0

Factor

x^{6} - x^{4} + 2 x^{3} - 6 x^{2} + 4 x : x (x - 1)^{2} (x + 2) (x^{2} + 2)

x (x - 1)^{2} (x + 2) (x^{2} + 2) \geq 0

Identify the intervals

x \leq - 2 or x \geq 0

9 p^{2} - 17 p - 2

y^{2} + 12 y + 35

6 m^{2} + 7 m - 3

a^{2} = 3 0^{2} - 0. 6^{2}

- 3 - (- 1)

What is x^6-x^4+2x^3-6x^2+4x>= 0 ?
The solution to x^6-x^4+2x^3-6x^2+4x>= 0 is x<=-2\lor x>= 0