What is (a^5b^2)^{-3}*(a^{-2})^{-3} ?

The solution to (a^5b^2)^{-3}*(a^{-2})^{-3} is 1/(a^9b^6)

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simplify (a^5b^2)^{-3}*(a^{-2})^{-3}

simplify

(a^{5} b^{2})^{- 3} \cdot (a^{- 2})^{- 3}

\frac{1}{a ^{9} b ^{6}}

Solution steps

(a^{5} b^{2})^{- 3} (a^{- 2})^{- 3}

Simplify

(a^{5} b^{2})^{- 3} : \frac{1}{a ^{15} b ^{6}}

= \frac{1}{a ^{15} b ^{6}} (a^{- 2})^{- 3}

Simplify

(a^{- 2})^{- 3} : a^{6}

= \frac{1}{a ^{15} b ^{6}} a^{6}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot a ^{6}}{a ^{15} b ^{6}}

Apply rule:

1 \cdot a = a

1 \cdot a^{6} = a^{6}

= \frac{a ^{6}}{a ^{15} b ^{6}}

Simplify

\frac{a ^{6}}{a ^{15}} : \frac{1}{a ^{9}}

= \frac{1}{a ^{9} b ^{6}}

\frac{x + 1}{x ^{2} + 6 x + 9} - \frac{1}{x ^{2} - 9}

lo g_{128} (\frac{1}{64})

12 x (x + 2) - 5 (2 x - 1)

9 x^{8}

\frac{x + 1}{x - 4} - \frac{x - 1}{( x - 4 ) ^{2}}

What is (a^5b^2)^{-3}*(a^{-2})^{-3} ?
The solution to (a^5b^2)^{-3}*(a^{-2})^{-3} is 1/(a^9b^6)