What is (x^2-25)/(x^2-4x-5) ?

The solution to (x^2-25)/(x^2-4x-5) is (x+5)/(x+1)

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simplify (x^2-25)/(x^2-4x-5)

simplify

\frac{x ^{2} - 25}{x ^{2} - 4 x - 5}

\frac{x + 5}{x + 1}

Solution steps

\frac{x ^{2} - 25}{x ^{2} - 4 x - 5}

Factor

x^{2} - 25 : (x + 5) (x - 5)

= \frac{( x + 5 ) ( x - 5 )}{x ^{2} - 4 x - 5}

Factor

x^{2} - 4 x - 5 : (x + 1) (x - 5)

= \frac{( x + 5 ) ( x - 5 )}{( x + 1 ) ( x - 5 )}

Cancel the common factor:

x - 5

= \frac{x + 5}{x + 1}

(x + 2) (x - 7) - (x + 6) (x - 11)

\frac{2}{3} \cdot 100

tan (θ) + \frac{1}{tan ( θ )}

\frac{2 e ^{- x}}{e ^{x}}

\frac{x}{7 x + x ^{2}}

What is (x^2-25)/(x^2-4x-5) ?
The solution to (x^2-25)/(x^2-4x-5) is (x+5)/(x+1)