What is 4/(b-2)+(b+1)/(b^2-4) ?

The solution to 4/(b-2)+(b+1)/(b^2-4) is (5b+9)/((b-2)(b+2))

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simplify 4/(b-2)+(b+1)/(b^2-4)

simplify

\frac{4}{b - 2} + \frac{b + 1}{b ^{2} - 4}

\frac{5 b + 9}{( b - 2 ) ( b + 2 )}

Solution steps

\frac{4}{b - 2} + \frac{b + 1}{b ^{2} - 4}

Least Common Multiplier of

b - 2, b^{2} - 4 : (b - 2) (b + 2)

Adjust Fractions based on the LCM

= \frac{4 ( b + 2 )}{( b - 2 ) ( b + 2 )} + \frac{b + 1}{( b - 2 ) ( b + 2 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{4 ( b + 2 ) + b + 1}{( b - 2 ) ( b + 2 )}

Simplify

4 (b + 2) + b + 1 : 5 b + 9

= \frac{5 b + 9}{( b - 2 ) ( b + 2 )}

\frac{4}{7} \cdot (- 2) - 1 - \frac{1}{4} \cdot (2 - \frac{1}{3})

H F + N a O H

1 - 2 (6 - (2 - (1 - x) + 1) - 1) = 5

x^{2} = 1

What is 4/(b-2)+(b+1)/(b^2-4) ?
The solution to 4/(b-2)+(b+1)/(b^2-4) is (5b+9)/((b-2)(b+2))