What is ((3x-1)-3)^2<= (3x+1)^2 ?

The solution to ((3x-1)-3)^2 = 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((3x-1)-3)^2<= (3x+1)^2

((3 x - 1) - 3)^{2} \leq (3 x + 1)^{2}

x \geq \frac{1}{2}

Solution steps

(3 x - 1 - 3)^{2} \leq (3 x + 1)^{2}

Rewrite in standard form

- 2 x + 1 \leq 0

Move

1

to the right side

- 2 x \leq - 1

Multiply both sides by

- 1

2 x \geq 1

Divide both sides by

2

x \geq \frac{1}{2}

\frac{( 2 x ^{3} ) ^{2} ( 3 y ^{4} ) ^{3}}{12 x ^{4} y ^{5}} - 4 x^{2} y^{7}

- 4 x = 8

x - \frac{1}{2} > \frac{1}{2} x - 5

86148.9 (1 - \frac{2}{10})^{1}

∣ 2 x - 5 ∣ < 6

What is ((3x-1)-3)^2<= (3x+1)^2 ?
The solution to ((3x-1)-3)^2<= (3x+1)^2 is x>= 1/2