What is (2x)^2(2x^{-1})^3 ?

The solution to (2x)^2(2x^{-1})^3 is (32)/x

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simplify (2x)^2(2x^{-1})^3

simplify

(2 x)^{2} (2 x^{- 1})^{3}

\frac{32}{x}

Solution steps

(2 x)^{2} (2 x^{- 1})^{3}

Simplify

(2 x)^{2} : 4 x^{2}

= 4 x^{2} (2 x^{- 1})^{3}

Simplify

(2 x^{- 1})^{3} : \frac{8}{x ^{3}}

= 4 x^{2} \frac{8}{x ^{3}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{4 x ^{2} \cdot 8}{x ^{3}}

Simplify

\frac{x ^{2}}{x ^{3}} : \frac{1}{x}

= \frac{4 \cdot 8}{x}

Multiply the numbers:

4 \cdot 8 = 32

= \frac{32}{x}

\frac{100 \cdot 15 \cdot 12 \cdot 2 \cdot 7}{9 \cdot 40 \cdot 25 \cdot 14}

\frac{( - 3 + i ) ^{6}}{( 1 - i ) ^{10}}

\frac{( 6 ^{3} \cdot 6 ^{2} ) ^{2}}{( 6 ^{4} ) ^{- 2}}

1 0^{2} - 5^{2}