What are the solutions to the equation 4x^2-17x-15=0 ?

The solutions to the equation 4x^2-17x-15=0 are x=5,x=-3/4

Find the zeros of 4x^2-17x-15=0

The zeros of 4x^2-17x-15=0 are x=5,x=-3/4

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4 x^{2} - 17 x - 15 = 0

x = 5, x = - \frac{3}{4}

Decimal Notation

x = 5, x = - 0.75

Solution steps

4 x^{2} - 17 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

(- 17)^{2} - 4 \cdot 4 (- 15) = 23

x_{1, 2} = \frac{- ( - 17 ) \pm 23}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 23}{2 \cdot 4}, x_{2} = \frac{- ( - 17 ) - 23}{2 \cdot 4}

x = \frac{- ( - 17 ) + 23}{2 \cdot 4} : 5

x = \frac{- ( - 17 ) - 23}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = 5, x = - \frac{3}{4}

6 x^{2} y + 4 x y^{2}

(\frac{2}{5})^{8}

\frac{3 x + 7}{x + 2} < 3

x^{2} - 1 + x + 1 = 0

10 x^{3} - 25 x^{2} + 4 x - 10

What are the solutions to the equation 4x^2-17x-15=0 ?
The solutions to the equation 4x^2-17x-15=0 are x=5,x=-3/4
Find the zeros of 4x^2-17x-15=0
The zeros of 4x^2-17x-15=0 are x=5,x=-3/4