What is (x^2+5x-36)/(x^2-49)*(x^2-11x+28) ?

The solution to (x^2+5x-36)/(x^2-49)*(x^2-11x+28) is ((x^2+5x-36)(x-4))/(x+7)

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simplify (x^2+5x-36)/(x^2-49)*(x^2-11x+28)

simplify

\frac{x ^{2} + 5 x - 36}{x ^{2} - 49} \cdot (x^{2} - 11 x + 28)

\frac{( x ^{2} + 5 x - 36 ) ( x - 4 )}{x + 7}

Solution steps

\frac{x ^{2} + 5 x - 36}{x ^{2} - 49} (x^{2} - 11 x + 28)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x ^{2} + 5 x - 36 ) ( x ^{2} - 11 x + 28 )}{x ^{2} - 49}

Factor

x^{2} - 11 x + 28 : (x - 4) (x - 7)

= \frac{( x ^{2} + 5 x - 36 ) ( x - 4 ) ( x - 7 )}{x ^{2} - 49}

Factor

x^{2} - 49 : (x + 7) (x - 7)

= \frac{( x ^{2} + 5 x - 36 ) ( x - 4 ) ( x - 7 )}{( x + 7 ) ( x - 7 )}

Cancel the common factor:

x - 7

= \frac{( x ^{2} + 5 x - 36 ) ( x - 4 )}{x + 7}

tan (θ) cos (θ) csc (θ)

(2 m + n)^{5}

\frac{\frac{17}{18} - \frac{7}{9}}{- \frac{1}{9} - \frac{5}{9}}

(- 8 x^{3} + 6 x^{2} - 3 x - 2) - (10 x^{3} - 12 x^{2} + 2 x - 1)

2 a a^{m} \cdot 3 b a^{1 - m}

What is (x^2+5x-36)/(x^2-49)*(x^2-11x+28) ?
The solution to (x^2+5x-36)/(x^2-49)*(x^2-11x+28) is ((x^2+5x-36)(x-4))/(x+7)