What is (a^2+a-1)-(a^2-a+1) ?

The solution to (a^2+a-1)-(a^2-a+1) is 2a-2

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simplify (a^2+a-1)-(a^2-a+1)

simplify

(a^{2} + a - 1) - (a^{2} - a + 1)

2 a - 2

Solution steps

(a^{2} + a - 1) - (a^{2} - a + 1)

Apply rule:

(a) = a

(a^{2} + a - 1) = a^{2} + a - 1

= a^{2} + a - 1 - (a^{2} - a + 1)

Apply the distributive law:

- (a - b) = - a + b

- (a^{2} - a + 1) = - a^{2} + a - 1

= a^{2} + a - 1 - a^{2} + a - 1

Group like terms

= a^{2} - a^{2} + a + a - 1 - 1

Add similar elements:

a^{2} - a^{2} = 0

= a + a - 1 - 1

Add similar elements:

a + a = 2 a

= 2 a - 1 - 1

Subtract the numbers:

- 1 - 1 = - 2

= 2 a - 2

\frac{1}{x - 2}

2 \div \frac{5}{6}

\frac{7 ( m - 6 )}{m - 6} \cdot \frac{5 m ( 7 m - 5 )}{7 ( 7 m - 5 )}

\frac{( 6 x ^{3} - x ^{2} - 16 x + 6 )}{( 2 x - 3 )}

\frac{4 ^{2}}{5 ^{2}} + \frac{4 ^{3}}{5 ^{3}} + \frac{4 ^{4}}{5 ^{4}}