What is 3(x^2y)^3*(2/x)^2 ?

The solution to 3(x^2y)^3*(2/x)^2 is 12x^4y^3

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simplify 3(x^2y)^3*(2/x)^2

simplify

3 (x^{2} y)^{3} \cdot (\frac{2}{x})^{2}

12 x^{4} y^{3}

Solution steps

3 (x^{2} y)^{3} (\frac{2}{x})^{2}

Simplify

(x^{2} y)^{3} : x^{6} y^{3}

= 3 x^{6} y^{3} (\frac{2}{x})^{2}

Simplify

(\frac{2}{x})^{2} : \frac{4}{x ^{2}}

= 3 x^{6} y^{3} \frac{4}{x ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 x ^{6} y ^{3} \cdot 4}{x ^{2}}

Simplify

\frac{x ^{6}}{x ^{2}} : x^{4}

= 3 x^{4} y^{3} \cdot 4

Multiply the numbers:

3 \cdot 4 = 12

= 12 x^{4} y^{3}

\frac{1}{2} + \frac{3}{4} + 2

\frac{1}{3} + \frac{1}{6} + \frac{1}{9}

(2 x + 3) (x - 3)

\frac{75}{25}

\frac{( 2 - 3 i )}{( 1 - 2 i )}