What is Dx[(3x^2+1)/(2x^2)] ?

The solution to Dx[(3x^2+1)/(2x^2)] is (D(3x^2+1))/(2x)

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simplify Dx[(3x^2+1)/(2x^2)]

simplify

D x [\frac{3 x ^{2} + 1}{2 x ^{2}}]

\frac{D ( 3 x ^{2} + 1 )}{2 x}

Solution steps

D x (\frac{3 x ^{2} + 1}{2 x ^{2}})

Apply rule:

(a) = a

(\frac{3 x ^{2} + 1}{2 x ^{2}}) = \frac{3 x ^{2} + 1}{2 x ^{2}}

= D x \frac{3 x ^{2} + 1}{2 x ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{D x ( 3 x ^{2} + 1 )}{2 x ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{D x ( 3 x ^{2} + 1 )}{2 xx}

Cancel the common factor:

x

= \frac{D ( 3 x ^{2} + 1 )}{2 x}

(cos (x))^{2} + (sin (x))^{2}

2000 \cdot (1.00175)^{(12 \cdot 5)}

\frac{1}{2} x - x

lo g_{10} (3) (81)

(- x^{2} + 4 x)^{2}

What is Dx[(3x^2+1)/(2x^2)] ?
The solution to Dx[(3x^2+1)/(2x^2)] is (D(3x^2+1))/(2x)