What are the solutions to the equation x^2-x=20^2 ?

The solutions to the equation x^2-x=20^2 are x=(1+sqrt(1601))/2 ,x=(1-sqrt(1601))/2

Find the zeros of x^2-x=20^2

The zeros of x^2-x=20^2 are x=(1+sqrt(1601))/2 ,x=(1-sqrt(1601))/2

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x^{2} - x = 2 0^{2}

x = \frac{1 + 1601}{2}, x = \frac{1 - 1601}{2}

Decimal Notation

x = 20.50624 \dots, x = - 19.50624 \dots

Solution steps

x^{2} - x = 2 0^{2}

Expand

2 0^{2} : 400

x^{2} - x = 400

Move

400

to the left side

x^{2} - x - 400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 400 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 400) = 1601

x_{1, 2} = \frac{- ( - 1 ) \pm 1601}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1601}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1601}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1601}{2 \cdot 1} : \frac{1 + 1601}{2}

x = \frac{- ( - 1 ) - 1601}{2 \cdot 1} : \frac{1 - 1601}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 1601}{2}, x = \frac{1 - 1601}{2}

\frac{7}{( x - 5 )} < 0

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\frac{65}{5}

100000 (1 + \frac{0.06}{1})^{0.06 (7)}

x^{2} - 17 x + 72 < 0

What are the solutions to the equation x^2-x=20^2 ?
The solutions to the equation x^2-x=20^2 are x=(1+sqrt(1601))/2 ,x=(1-sqrt(1601))/2
Find the zeros of x^2-x=20^2
The zeros of x^2-x=20^2 are x=(1+sqrt(1601))/2 ,x=(1-sqrt(1601))/2