What is (c^2+7c+10)/(c^2+2c-15)*(4c+12)/(3c+15) ?

The solution to (c^2+7c+10)/(c^2+2c-15)*(4c+12)/(3c+15) is ((c+2)(4c+12))/((c-3)(3c+15))

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simplify (c^2+7c+10)/(c^2+2c-15)*(4c+12)/(3c+15)

simplify

\frac{c ^{2} + 7 c + 10}{c ^{2} + 2 c - 15} \cdot \frac{4 c + 12}{3 c + 15}

\frac{( c + 2 ) ( 4 c + 12 )}{( c - 3 ) ( 3 c + 15 )}

Solution steps

\frac{c ^{2} + 7 c + 10}{c ^{2} + 2 c - 15} \cdot \frac{4 c + 12}{3 c + 15}

Cancel

\frac{c ^{2} + 7 c + 10}{c ^{2} + 2 c - 15} : \frac{c + 2}{c - 3}

= \frac{c + 2}{c - 3} \cdot \frac{4 c + 12}{3 c + 15}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( c + 2 ) ( 4 c + 12 )}{( c - 3 ) ( 3 c + 15 )}

12 x^{2} - 4 x

(\frac{1 + cos ( 2 x )}{2})^{2}

(n + 5 k)^{3}

\frac{x + 3}{x ^{3} + 27}

(x - 1) (x - 2) (x - 5)

What is (c^2+7c+10)/(c^2+2c-15)*(4c+12)/(3c+15) ?
The solution to (c^2+7c+10)/(c^2+2c-15)*(4c+12)/(3c+15) is ((c+2)(4c+12))/((c-3)(3c+15))