What is (3-2i)/(-1+i) ?

The solution to (3-2i)/(-1+i) is -5/2-1/2 i

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simplify (3-2i)/(-1+i)

simplify

\frac{3 - 2 i}{- 1 + i}

- \frac{5}{2} - \frac{1}{2} i

Solution steps

\frac{3 - 2 i}{- 1 + i}

Multiply by the conjugate

\frac{- 1 - i}{- 1 - i}

= \frac{( 3 - 2 i ) ( - 1 - i )}{( - 1 + i ) ( - 1 - i )}

Simplify

\frac{( 3 - 2 i ) ( - 1 - i )}{( - 1 + i ) ( - 1 - i )} : \frac{- 5 - i}{2}

= \frac{- 5 - i}{2}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{- 5}{2} + \frac{- 1}{2} i

Simplify

\frac{- 5}{2} + \frac{- 1}{2} i : - \frac{5}{2} - \frac{1}{2} i

= - \frac{5}{2} - \frac{1}{2} i

\frac{3}{x ^{2} - 2 x + 1} + \frac{2}{x ^{2} - 1}

\frac{16 x ^{12}}{x ^{4}} - 3 x^{6} (x^{- 1})^{2}

- 11 ab - 15 ab + 26 ab

23 + 43

(7 x^{2} - 12 y^{3}) (7 x^{2} + 12 y^{3})