What is ((10i))/((1-2i)) ?

The solution to ((10i))/((1-2i)) is -4+2i

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simplify ((10i))/((1-2i))

simplify

\frac{( 10 i )}{( 1 - 2 i )}

- 4 + 2 i

Solution steps

\frac{10 i}{1 - 2 i}

Multiply by the conjugate

\frac{1 + 2 i}{1 + 2 i}

= \frac{10 i ( 1 + 2 i )}{( 1 - 2 i ) ( 1 + 2 i )}

Simplify

\frac{10 i ( 1 + 2 i )}{( 1 - 2 i ) ( 1 + 2 i )} : \frac{10 i - 20}{5}

= \frac{10 i - 20}{5}

Rewrite in standard complex form:

- 4 + 2 i

= - 4 + 2 i

\frac{1}{2} (9.8)

x^{4} - 6 x^{3} - 11 x^{2} + 96 x - 80

[(9 x^{\frac{1}{2}} y^{- 3}) (2 x^{- 1} y)^{2}]^{\frac{1}{2}}

4 x^{2} + 4 - 5 x + x - 2 x^{2} + 8

23 \cdot 35