What are the solutions to the equation 10x^2+2=-3x ?

The solutions to the equation 10x^2+2=-3x are x=-3/20+i(sqrt(71))/(20),x=-3/20-i(sqrt(71))/(20)

Find the zeros of 10x^2+2=-3x

The zeros of 10x^2+2=-3x are x=-3/20+i(sqrt(71))/(20),x=-3/20-i(sqrt(71))/(20)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

10 x^{2} + 2 = - 3 x

x = - \frac{3}{20} + i \frac{71}{20}, x = - \frac{3}{20} - i \frac{71}{20}

Solution steps

10 x^{2} + 2 = - 3 x

Move

3 x

to the left side

10 x^{2} + 2 + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

10 x^{2} + 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 10 \cdot 2}{2 \cdot 10}

Simplify

3^{2} - 4 \cdot 10 \cdot 2 : 71 i

x_{1, 2} = \frac{- 3 \pm 71 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 3 + 71 i}{2 \cdot 10}, x_{2} = \frac{- 3 - 71 i}{2 \cdot 10}

x = \frac{- 3 + 71 i}{2 \cdot 10} : - \frac{3}{20} + i \frac{71}{20}

x = \frac{- 3 - 71 i}{2 \cdot 10} : - \frac{3}{20} - i \frac{71}{20}

The solutions to the quadratic equation are:

x = - \frac{3}{20} + i \frac{71}{20}, x = - \frac{3}{20} - i \frac{71}{20}

2 x + x^{2}

3 \leq x \leq 5

\frac{6 + 4 i}{i}

18 x y^{2} + 24 x y + 8 x

3^{\frac{5}{6}} \cdot 24 3^{\frac{5}{6}}

What are the solutions to the equation 10x^2+2=-3x ?
The solutions to the equation 10x^2+2=-3x are x=-3/20+i(sqrt(71))/(20),x=-3/20-i(sqrt(71))/(20)
Find the zeros of 10x^2+2=-3x
The zeros of 10x^2+2=-3x are x=-3/20+i(sqrt(71))/(20),x=-3/20-i(sqrt(71))/(20)