What is ((6x^3+11x^2-47x+20))/((2x^2+7x-4)) ?

The solution to ((6x^3+11x^2-47x+20))/((2x^2+7x-4)) is 3x-5

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simplify ((6x^3+11x^2-47x+20))/((2x^2+7x-4))

simplify

\frac{( 6 x ^{3} + 11 x ^{2} - 47 x + 20 )}{( 2 x ^{2} + 7 x - 4 )}

3 x - 5

Solution steps

\frac{6 x ^{3} + 11 x ^{2} - 47 x + 20}{2 x ^{2} + 7 x - 4}

Factor

6 x^{3} + 11 x^{2} - 47 x + 20 : (2 x - 1) (3 x - 5) (x + 4)

= \frac{( 2 x - 1 ) ( 3 x - 5 ) ( x + 4 )}{2 x ^{2} + 7 x - 4}

Factor

2 x^{2} + 7 x - 4 : (2 x - 1) (x + 4)

= \frac{( 2 x - 1 ) ( 3 x - 5 ) ( x + 4 )}{( 2 x - 1 ) ( x + 4 )}

Cancel the common factor:

2 x - 1

= \frac{( 3 x - 5 ) ( x + 4 )}{x + 4}

Cancel the common factor:

x + 4

= 3 x - 5

2 x^{2} + 6 x + 2

- 2 \cdot 2 x

\frac{x + y}{x y} - \frac{x + 2 y}{x y + y ^{2}} - \frac{y}{x ^{2} + x y}

i^{204}

(csc (x) - 1) (csc (x) + 1)

What is ((6x^3+11x^2-47x+20))/((2x^2+7x-4)) ?
The solution to ((6x^3+11x^2-47x+20))/((2x^2+7x-4)) is 3x-5