What are the solutions to the equation m^2+4m-2=0 ?

The solutions to the equation m^2+4m-2=0 are m=-2+sqrt(6),m=-2-sqrt(6)

Find the zeros of m^2+4m-2=0

The zeros of m^2+4m-2=0 are m=-2+sqrt(6),m=-2-sqrt(6)

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m^{2} + 4 m - 2 = 0

m = - 2 + 6, m = - 2 - 6

Decimal Notation

m = 0.44948 \dots, m = - 4.44948 \dots

Solution steps

m^{2} + 4 m - 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 2) = 26

m_{1, 2} = \frac{- 4 \pm 2 6}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 2 6}{2 \cdot 1}, m_{2} = \frac{- 4 - 2 6}{2 \cdot 1}

m = \frac{- 4 + 2 6}{2 \cdot 1} : - 2 + 6

m = \frac{- 4 - 2 6}{2 \cdot 1} : - 2 - 6

The solutions to the quadratic equation are:

m = - 2 + 6, m = - 2 - 6

\frac{1 + 43 i}{- 5 + 7 i}

12 = k (ln (7)) + \frac{20}{ln ( 2.6 )} - k

(- 1)^{\frac{1}{5}}

43 \cdot 2

x^{2} - 6 x < - 8

What are the solutions to the equation m^2+4m-2=0 ?
The solutions to the equation m^2+4m-2=0 are m=-2+sqrt(6),m=-2-sqrt(6)
Find the zeros of m^2+4m-2=0
The zeros of m^2+4m-2=0 are m=-2+sqrt(6),m=-2-sqrt(6)