What is (3x^2-2x+5)-(2x^2-5x+1) ?

The solution to (3x^2-2x+5)-(2x^2-5x+1) is x^2+3x+4

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simplify (3x^2-2x+5)-(2x^2-5x+1)

simplify

(3 x^{2} - 2 x + 5) - (2 x^{2} - 5 x + 1)

x^{2} + 3 x + 4

Solution steps

(3 x^{2} - 2 x + 5) - (2 x^{2} - 5 x + 1)

Apply rule:

(a) = a

(3 x^{2} - 2 x + 5) = 3 x^{2} - 2 x + 5

= 3 x^{2} - 2 x + 5 - (2 x^{2} - 5 x + 1)

Apply the distributive law:

- (a - b) = - a + b

- (2 x^{2} - 5 x + 1) = - 2 x^{2} + 5 x - 1

= 3 x^{2} - 2 x + 5 - 2 x^{2} + 5 x - 1

Group like terms

= 3 x^{2} - 2 x^{2} - 2 x + 5 x + 5 - 1

Add similar elements:

3 x^{2} - 2 x^{2} = x^{2}

= x^{2} - 2 x + 5 x + 5 - 1

Add similar elements:

- 2 x + 5 x = 3 x

= x^{2} + 3 x + 5 - 1

Subtract the numbers:

5 - 1 = 4

= x^{2} + 3 x + 4

\frac{p ^{2} + 7 p + 10}{p + 5} \cdot \frac{1}{p + 2}

\frac{380}{3}

\frac{1}{3} \cdot \frac{1}{3}

45 x^{3} + 18 x^{2} - 5 x - 2

\frac{( n - 1 ) !}{( n + 2 ) !}

What is (3x^2-2x+5)-(2x^2-5x+1) ?
The solution to (3x^2-2x+5)-(2x^2-5x+1) is x^2+3x+4