What is ((x^{-1}y^2z^4)/(z^5x^2y^{-1)})^{-3} ?

The solution to ((x^{-1}y^2z^4)/(z^5x^2y^{-1)})^{-3} is (x^9z^3)/(y^9)

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simplify ((x^{-1}y^2z^4)/(z^5x^2y^{-1)})^{-3}

simplify

(\frac{x ^{- 1} y ^{2} z ^{4}}{z ^{5} x ^{2} y ^{- 1}})^{- 3}

\frac{x ^{9} z ^{3}}{y ^{9}}

Solution steps

(\frac{x ^{- 1} y ^{2} z ^{4}}{z ^{5} x ^{2} y ^{- 1}})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{x ^{- 1} y ^{2} z ^{4}}{z ^{5} x ^{2} y ^{- 1}})^{- 3} = \frac{1}{( \frac{x ^{- 1} y ^{2} z ^{4}}{z ^{5} x ^{2} y ^{- 1}} ) ^{3}}

= \frac{1}{( \frac{x ^{- 1} y ^{2} z ^{4}}{z ^{5} x ^{2} y ^{- 1}} ) ^{3}}

Simplify

(\frac{x ^{- 1} y ^{2} z ^{4}}{z ^{5} x ^{2} y ^{- 1}})^{3} : \frac{y ^{9}}{x ^{9} z ^{3}}

= \frac{1}{\frac{y ^{9}}{x ^{9} z ^{3}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{9} z ^{3}}{y ^{9}}

- 20 + - 45

1 - tan^{2} (θ)

\frac{9 n}{2 n} \cdot \frac{7}{5 n}

3 \cdot \frac{3}{3}

1 - cos (2 θ)

What is ((x^{-1}y^2z^4)/(z^5x^2y^{-1)})^{-3} ?
The solution to ((x^{-1}y^2z^4)/(z^5x^2y^{-1)})^{-3} is (x^9z^3)/(y^9)