What is factor 2x^4-9x^3+15x^2-2x-6 ?

The solution to factor 2x^4-9x^3+15x^2-2x-6 is (x-1)(2x+1)(x^2-4x+6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 2x^4-9x^3+15x^2-2x-6

factor

2 x^{4} - 9 x^{3} + 15 x^{2} - 2 x - 6

(x - 1) (2 x + 1) (x^{2} - 4 x + 6)

Solution steps

2 x^{4} - 9 x^{3} + 15 x^{2} - 2 x - 6

Use the rational root theorem

= (x - 1) \frac{2 x ^{4} - 9 x ^{3} + 15 x ^{2} - 2 x - 6}{x - 1}

\frac{2 x ^{4} - 9 x ^{3} + 15 x ^{2} - 2 x - 6}{x - 1} = 2 x^{3} - 7 x^{2} + 8 x + 6

= (x - 1) (2 x^{3} - 7 x^{2} + 8 x + 6)

Factor

2 x^{3} - 7 x^{2} + 8 x + 6 : (2 x + 1) (x^{2} - 4 x + 6)

= (x - 1) (2 x + 1) (x^{2} - 4 x + 6)

(3 y - 5)^{2}

\frac{9 x + 27}{27 x}

\frac{2}{8} + \frac{7}{5} - \frac{3}{9}

3 x - (6 x + 1) + (x - 3)

\frac{a}{b ^{2} + ab} - \frac{b}{a ^{2} + ab}

What is factor 2x^4-9x^3+15x^2-2x-6 ?
The solution to factor 2x^4-9x^3+15x^2-2x-6 is (x-1)(2x+1)(x^2-4x+6)