What are the solutions to the equation -x^2-4x+4=0 ?

The solutions to the equation -x^2-4x+4=0 are x=-2(1+sqrt(2)),x=2(sqrt(2)-1)

Find the zeros of -x^2-4x+4=0

The zeros of -x^2-4x+4=0 are x=-2(1+sqrt(2)),x=2(sqrt(2)-1)

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- x^{2} - 4 x + 4 = 0

x = - 2 (1 + 2), x = 2 (2 - 1)

Decimal Notation

x = - 4.82842 \dots, x = 0.82842 \dots

Solution steps

- x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

(- 4)^{2} - 4 (- 1) \cdot 4 = 42

x_{1, 2} = \frac{- ( - 4 ) \pm 4 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 2}{2 ( - 1 )}, x_{2} = \frac{- ( - 4 ) - 4 2}{2 ( - 1 )}

x = \frac{- ( - 4 ) + 4 2}{2 ( - 1 )} : - 2 (1 + 2)

x = \frac{- ( - 4 ) - 4 2}{2 ( - 1 )} : 2 (2 - 1)

The solutions to the quadratic equation are:

x = - 2 (1 + 2), x = 2 (2 - 1)

5 (2 y) - y = 72

\frac{2 x - 1}{3} = 5

36 - x^{4} y^{4}

k - 3 k = 6 k + 5 - 8 k

2 ∣ 2 x + 5 ∣ + 1 = 3

What are the solutions to the equation -x^2-4x+4=0 ?
The solutions to the equation -x^2-4x+4=0 are x=-2(1+sqrt(2)),x=2(sqrt(2)-1)
Find the zeros of -x^2-4x+4=0
The zeros of -x^2-4x+4=0 are x=-2(1+sqrt(2)),x=2(sqrt(2)-1)