What is expand (2+5x)((1-x)/2)^8 ?

The solution to expand (2+5x)((1-x)/2)^8 is ((1-x)^8)/(128)+(5(1-x)^8x)/(256)

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expand (2+5x)((1-x)/2)^8

expand

(2 + 5 x) (\frac{1 - x}{2})^{8}

\frac{( 1 - x ) ^{8}}{128} + \frac{5 ( 1 - x ) ^{8} x}{256}

Solution steps

(2 + 5 x) (\frac{1 - x}{2})^{8}

= (\frac{1 - x}{2})^{8} (2 + 5 x)

Apply the distributive law:

a (b + c) = ab + a c

(\frac{1 - x}{2})^{8} (2 + 5 x) = (\frac{1 - x}{2})^{8} \cdot 2 + (\frac{1 - x}{2})^{8} \cdot 5 x

= (\frac{1 - x}{2})^{8} \cdot 2 + (\frac{1 - x}{2})^{8} \cdot 5 x

Simplify

(\frac{1 - x}{2})^{8} \cdot 2 + (\frac{1 - x}{2})^{8} \cdot 5 x : \frac{( 1 - x ) ^{8}}{128} + \frac{5 ( 1 - x ) ^{8} x}{256}

= \frac{( 1 - x ) ^{8}}{128} + \frac{5 ( 1 - x ) ^{8} x}{256}

1 3^{2} - 1 2^{2} + (6 - 4)^{2} \cdot 8 - (10 - 8)^{2}

0.0 5^{3}

\frac{\frac{x ^{2} - 7 x + 12}{x ^{2} - 4 x}}{\frac{x ^{2} - 9}{x}}

\frac{1}{x + h + 2} - \frac{1}{x + 2}

5 a + 2 a

What is expand (2+5x)((1-x)/2)^8 ?
The solution to expand (2+5x)((1-x)/2)^8 is ((1-x)^8)/(128)+(5(1-x)^8x)/(256)