What are the solutions to the equation 6q^2-6q=5q^2-8q+24 ?

The solutions to the equation 6q^2-6q=5q^2-8q+24 are q=-6,q=4

Find the zeros of 6q^2-6q=5q^2-8q+24

The zeros of 6q^2-6q=5q^2-8q+24 are q=-6,q=4

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6 q^{2} - 6 q = 5 q^{2} - 8 q + 24

q = - 6, q = 4

Solution steps

6 q^{2} - 6 q = 5 q^{2} - 8 q + 24

Switch sides

5 q^{2} - 8 q + 24 = 6 q^{2} - 6 q

Move

6 q

to the left side

5 q^{2} - 2 q + 24 = 6 q^{2}

Move

6 q^{2}

to the left side

- q^{2} - 2 q + 24 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 24}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 24 = 10

q_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 ( - 1 )}

Separate the solutions

q_{1} = \frac{- ( - 2 ) + 10}{2 ( - 1 )}, q_{2} = \frac{- ( - 2 ) - 10}{2 ( - 1 )}

q = \frac{- ( - 2 ) + 10}{2 ( - 1 )} : - 6

q = \frac{- ( - 2 ) - 10}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

q = - 6, q = 4

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1 - \frac{4}{9}

\frac{x ( x + 2 )}{( x - 5 )} - 2 < x < 0

What are the solutions to the equation 6q^2-6q=5q^2-8q+24 ?
The solutions to the equation 6q^2-6q=5q^2-8q+24 are q=-6,q=4
Find the zeros of 6q^2-6q=5q^2-8q+24
The zeros of 6q^2-6q=5q^2-8q+24 are q=-6,q=4