What is (1-a^2b^4c^8)/(1-ab^2c^4) ?

The solution to (1-a^2b^4c^8)/(1-ab^2c^4) is 1+ab^2c^4

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simplify (1-a^2b^4c^8)/(1-ab^2c^4)

simplify

\frac{1 - a ^{2} b ^{4} c ^{8}}{1 - a b ^{2} c ^{4}}

1 + a b^{2} c^{4}

Solution steps

\frac{1 - a ^{2} b ^{4} c ^{8}}{1 - a b ^{2} c ^{4}}

Factor

1 - a^{2} b^{4} c^{8} : (1 + a b^{2} c^{4}) (1 - a b^{2} c^{4})

= \frac{( 1 + a b ^{2} c ^{4} ) ( 1 - a b ^{2} c ^{4} )}{1 - a b ^{2} c ^{4}}

Cancel the common factor:

1 - a b^{2} c^{4}

= 1 + a b^{2} c^{4}

\frac{4 x ^{3}}{16 x ^{4} - 48 x ^{3}}

c^{0}

\frac{5}{8} \cdot \frac{2}{3}

(2 + i) (- 4 + i)

What is (1-a^2b^4c^8)/(1-ab^2c^4) ?
The solution to (1-a^2b^4c^8)/(1-ab^2c^4) is 1+ab^2c^4