What are the solutions to the equation 6^2+10^2=c^2 ?

The solutions to the equation 6^2+10^2=c^2 are c=2sqrt(34),c=-2sqrt(34)

Find the zeros of 6^2+10^2=c^2

The zeros of 6^2+10^2=c^2 are c=2sqrt(34),c=-2sqrt(34)

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6^{2} + 1 0^{2} = c^{2}

c = 234, c = - 234

Solution steps

6^{2} + 1 0^{2} = c^{2}

Switch sides

c^{2} = 6^{2} + 1 0^{2}

Simplify

6^{2} + 1 0^{2} : 136

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 136, c = - 136

136 = 234

- 136 = - 234

c = 234, c = - 234

4 x^{2} + 3 x = 7 x + 3

- 2 x + 3 = 2 x + 3

∣ d + 1 ∣ = 7

8 x^{5} - 98 x^{3}

2 a^{2} x - 5 a^{2} y + 15 b y - 6 b x

What are the solutions to the equation 6^2+10^2=c^2 ?
The solutions to the equation 6^2+10^2=c^2 are c=2sqrt(34),c=-2sqrt(34)
Find the zeros of 6^2+10^2=c^2
The zeros of 6^2+10^2=c^2 are c=2sqrt(34),c=-2sqrt(34)