What is ((2x^3+10x^2+7x-15))/((x+3)) ?

The solution to ((2x^3+10x^2+7x-15))/((x+3)) is 2x^2+4x-5

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simplify ((2x^3+10x^2+7x-15))/((x+3))

simplify

\frac{( 2 x ^{3} + 10 x ^{2} + 7 x - 15 )}{( x + 3 )}

2 x^{2} + 4 x - 5

Solution steps

\frac{2 x ^{3} + 10 x ^{2} + 7 x - 15}{x + 3}

Factor

2 x^{3} + 10 x^{2} + 7 x - 15 : (x + 3) (2 x^{2} + 4 x - 5)

= \frac{( x + 3 ) ( 2 x ^{2} + 4 x - 5 )}{x + 3}

Cancel the common factor:

x + 3

= 2 x^{2} + 4 x - 5

cos^{2} (4 x) - sin^{2} (4 x)

(x + 1) \cdot (x + 3)

- 2 x^{2} + 2 x

cos^{2} (\frac{θ}{3}) - sin^{2} (\frac{θ}{3})

\frac{1}{2} x^{\frac{- 1}{2}}

What is ((2x^3+10x^2+7x-15))/((x+3)) ?
The solution to ((2x^3+10x^2+7x-15))/((x+3)) is 2x^2+4x-5