What is expand (x-3)(2x^2-5x+1) ?

The solution to expand (x-3)(2x^2-5x+1) is 2x^3-11x^2+16x-3

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expand (x-3)(2x^2-5x+1)

expand

(x - 3) (2 x^{2} - 5 x + 1)

2 x^{3} - 11 x^{2} + 16 x - 3

Solution steps

(x - 3) (2 x^{2} - 5 x + 1)

Distribute parentheses

= x \cdot 2 x^{2} + x (- 5 x) + x \cdot 1 - 3 \cdot 2 x^{2} - 3 (- 5 x) - 3 \cdot 1

Simplify

x \cdot 2 x^{2} + x (- 5 x) + x \cdot 1 - 3 \cdot 2 x^{2} - 3 (- 5 x) - 3 \cdot 1 : 2 x^{3} - 11 x^{2} + 16 x - 3

= 2 x^{3} - 11 x^{2} + 16 x - 3

2 a^{2} x + 2 a x + 2 x - a^{2} - a - 1

\frac{4}{12} \cdot \frac{3}{11}

π \cdot 1 2^{2}

9 \cdot (- 8)

(3 x + \frac{1}{2})^{3}

What is expand (x-3)(2x^2-5x+1) ?
The solution to expand (x-3)(2x^2-5x+1) is 2x^3-11x^2+16x-3