What is 6sqrt((64w^6)/(18w^2x^3)) ?

The solution to 6sqrt((64w^6)/(18w^2x^3)) is (8sqrt(2)w^2)/(xsqrt(x))

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simplify 6sqrt((64w^6)/(18w^2x^3))

simplify

6 \frac{64 w ^{6}}{18 w ^{2} x ^{3}}

\frac{8 2 w ^{2}}{x x}

Solution steps

6 \frac{64 w ^{6}}{18 w ^{2} x ^{3}}

Cancel

\frac{64 w ^{6}}{18 w ^{2} x ^{3}} : \frac{32 w ^{4}}{9 x ^{3}}

= 6 \frac{32 w ^{4}}{9 x ^{3}}

Apply radical rule:

\frac{a}{b} = \frac{a}{b},

assuming

a \geq 0, b \geq 0

\frac{32 w ^{4}}{9 x ^{3}} = \frac{32 w ^{4}}{9 x ^{3}}

= 6 \cdot \frac{32 w ^{4}}{9 x ^{3}}

Simplify

32 w^{4} : 42 w^{2}

= 6 \cdot \frac{4 2 w ^{2}}{9 x ^{3}}

Simplify

9 x^{3} : 3 x x

= 6 \cdot \frac{4 2 w ^{2}}{3 x x}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{6 \cdot 4 2 w ^{2}}{3 x x}

Cancel

\frac{6 \cdot 4 2 w ^{2}}{3 x x} : \frac{2 \cdot 4 2 w ^{2}}{x x}

= \frac{2 \cdot 4 2 w ^{2}}{x x}

Multiply the numbers:

2 \cdot 4 = 8

= \frac{8 2 w ^{2}}{x x}

4 + 1

x \frac{1}{x}

\frac{1}{6} \cdot \frac{5}{6}

825

sin^{2} (y) - cos^{2} (y)

What is 6sqrt((64w^6)/(18w^2x^3)) ?
The solution to 6sqrt((64w^6)/(18w^2x^3)) is (8sqrt(2)w^2)/(xsqrt(x))