What are the solutions to the equation 3x^2+4x+12=0 ?

The solutions to the equation 3x^2+4x+12=0 are x=-2/3+i(4sqrt(2))/3 ,x=-2/3-i(4sqrt(2))/3

Find the zeros of 3x^2+4x+12=0

The zeros of 3x^2+4x+12=0 are x=-2/3+i(4sqrt(2))/3 ,x=-2/3-i(4sqrt(2))/3

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3 x^{2} + 4 x + 12 = 0

x = - \frac{2}{3} + i \frac{4 2}{3}, x = - \frac{2}{3} - i \frac{4 2}{3}

Solution steps

3 x^{2} + 4 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 12}{2 \cdot 3}

Simplify

4^{2} - 4 \cdot 3 \cdot 12 : 82 i

x_{1, 2} = \frac{- 4 \pm 8 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 8 2 i}{2 \cdot 3}, x_{2} = \frac{- 4 - 8 2 i}{2 \cdot 3}

x = \frac{- 4 + 8 2 i}{2 \cdot 3} : - \frac{2}{3} + i \frac{4 2}{3}

x = \frac{- 4 - 8 2 i}{2 \cdot 3} : - \frac{2}{3} - i \frac{4 2}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{3} + i \frac{4 2}{3}, x = - \frac{2}{3} - i \frac{4 2}{3}

3 x^{3} - 3 x^{2} - 6 x

3 x^{3} + 21 x^{2} + 18 x

- 6 (6 x + 8) = - 336

\frac{20 x ^{6} y ^{3}}{15 x y ^{- 2}}

(x - 4) (x + 2) = 0

What are the solutions to the equation 3x^2+4x+12=0 ?
The solutions to the equation 3x^2+4x+12=0 are x=-2/3+i(4sqrt(2))/3 ,x=-2/3-i(4sqrt(2))/3
Find the zeros of 3x^2+4x+12=0
The zeros of 3x^2+4x+12=0 are x=-2/3+i(4sqrt(2))/3 ,x=-2/3-i(4sqrt(2))/3