What is (3-2i)+(4+5i) ?

The solution to (3-2i)+(4+5i) is 7+3i

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simplify (3-2i)+(4+5i)

simplify

(3 - 2 i) + (4 + 5 i)

7 + 3 i

Solution steps

(3 - 2 i) + (4 + 5 i)

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (3 + 4) + (- 2 + 5) i

Simplify

(3 + 4) + (- 2 + 5) i : 7 + 3 i

= 7 + 3 i

- 6 \cdot 1

\frac{7}{63}

(6 - \frac{1}{2} a)^{6}

\frac{cos ( x )}{1 - sin ( x )} + \frac{cos ( x )}{1 + sin ( x )}

\frac{csc ^{2} ( x ) - cot ^{2} ( x )}{sin ( - x ) cot ( x )}