What is 2/(k+3)+1/(k-1) ?

The solution to 2/(k+3)+1/(k-1) is (3k+1)/((k+3)(k-1))

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simplify 2/(k+3)+1/(k-1)

simplify

\frac{2}{k + 3} + \frac{1}{k - 1}

\frac{3 k + 1}{( k + 3 ) ( k - 1 )}

Solution steps

\frac{2}{k + 3} + \frac{1}{k - 1}

Least Common Multiplier of

k + 3, k - 1 : (k + 3) (k - 1)

Adjust Fractions based on the LCM

= \frac{2 ( k - 1 )}{( k + 3 ) ( k - 1 )} + \frac{k + 3}{( k + 3 ) ( k - 1 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{2 ( k - 1 ) + k + 3}{( k + 3 ) ( k - 1 )}

Simplify

2 (k - 1) + k + 3 : 3 k + 1

= \frac{3 k + 1}{( k + 3 ) ( k - 1 )}

6 \cdot \frac{5}{4}

12 x^{3} - 56 x^{2} + 87 x - 45

\frac{2}{sin ( x )}

(- x^{2} + 4 x + 2)^{2}

- x (7 x - 8)

What is 2/(k+3)+1/(k-1) ?
The solution to 2/(k+3)+1/(k-1) is (3k+1)/((k+3)(k-1))