What are the solutions to the equation x=4x^2 ?

The solutions to the equation x=4x^2 are x= 1/4 ,x=0

Find the zeros of x=4x^2

The zeros of x=4x^2 are x= 1/4 ,x=0

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x = 4 x^{2}

x = \frac{1}{4}, x = 0

Decimal Notation

x = 0.25, x = 0

Solution steps

x = 4 x^{2}

Switch sides

4 x^{2} = x

Move

x

to the left side

4 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 4}

x = \frac{- ( - 1 ) + 1}{2 \cdot 4} : \frac{1}{4}

x = \frac{- ( - 1 ) - 1}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 0

- 4 ∣ 6 - x ∣ < - 8

\frac{1}{4} - 2

(\frac{8}{5})^{0}

7 - n = 15

2 x^{2} - 8 x - 10 = 32

What are the solutions to the equation x=4x^2 ?
The solutions to the equation x=4x^2 are x= 1/4 ,x=0
Find the zeros of x=4x^2
The zeros of x=4x^2 are x= 1/4 ,x=0