What is ((q^{-1}+q^3)^2)/(q^{-3)} ?

The solution to ((q^{-1}+q^3)^2)/(q^{-3)} is (q^4+1)^2q

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((q^{-1}+q^3)^2)/(q^{-3)}

simplify

\frac{( q ^{- 1} + q ^{3} ) ^{2}}{q ^{- 3}}

(q^{4} + 1)^{2} q

Solution steps

\frac{( q ^{- 1} + q ^{3} ) ^{2}}{q ^{- 3}}

Simplify

(q^{- 1} + q^{3})^{2} : \frac{( q ^{4} + 1 ) ^{2}}{q ^{2}}

= \frac{\frac{( q ^{4} + 1 ) ^{2}}{q ^{2}}}{q ^{- 3}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( q ^{4} + 1 ) ^{2}}{q ^{2} q ^{- 3}}

Simplify

q^{2} q^{- 3} : \frac{1}{q}

= \frac{( q ^{4} + 1 ) ^{2}}{\frac{1}{q}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{( q ^{4} + 1 ) ^{2} q}{1}

Apply the fraction rule:

\frac{a}{1} = a

= (q^{4} + 1)^{2} q

lo g_{10} (x) lo g_{10} (x)

x (x + 1) (x + 3)

\frac{7.2}{0.8 - ( 2.3 ) ^{2} + 6.5 \cdot 5.1}

2 5^{\frac{2}{4}}

\frac{15}{10}

What is ((q^{-1}+q^3)^2)/(q^{-3)} ?
The solution to ((q^{-1}+q^3)^2)/(q^{-3)} is (q^4+1)^2q