What is (1+2i)/(1-2i)+(2+i)/(1+2i) ?

The solution to (1+2i)/(1-2i)+(2+i)/(1+2i) is 1/5+1/5 i

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simplify (1+2i)/(1-2i)+(2+i)/(1+2i)

simplify

\frac{1 + 2 i}{1 - 2 i} + \frac{2 + i}{1 + 2 i}

\frac{1}{5} + \frac{1}{5} i

Solution steps

\frac{1 + 2 i}{1 - 2 i} + \frac{2 + i}{1 + 2 i}

\frac{1 + 2 i}{1 - 2 i} = \frac{4 i - 3}{5}

\frac{2 + i}{1 + 2 i} = \frac{4 - 3 i}{5}

= \frac{4 i - 3}{5} + \frac{4 - 3 i}{5}

Join

\frac{4 i - 3}{5} + \frac{4 - 3 i}{5} : \frac{i + 1}{5}

= \frac{i + 1}{5}

Rewrite in standard complex form:

\frac{1}{5} + \frac{1}{5} i

= \frac{1}{5} + \frac{1}{5} i

32 n^{\frac{3}{2}}

(\frac{1}{3 ( x - 1 ) ^{\frac{2}{3}}})^{2}

2 \cdot 1 0^{4} + 3 \cdot 1 0^{4}

\frac{tan ( x )}{cos ^{2} ( x )}

What is (1+2i)/(1-2i)+(2+i)/(1+2i) ?
The solution to (1+2i)/(1-2i)+(2+i)/(1+2i) is 1/5+1/5 i