What is (9/(b^2-b-12))/(\frac{b-5){b^2-b-12}} ?

The solution to (9/(b^2-b-12))/(\frac{b-5){b^2-b-12}} is 9/(b-5)

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simplify (9/(b^2-b-12))/(\frac{b-5){b^2-b-12}}

simplify

\frac{\frac{9}{b ^{2} - b - 12}}{\frac{b - 5}{b ^{2} - b - 12}}

\frac{9}{b - 5}

Solution steps

\frac{\frac{9}{b ^{2} - b - 12}}{\frac{b - 5}{b ^{2} - b - 12}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{9 ( b ^{2} - b - 12 )}{( b ^{2} - b - 12 ) ( b - 5 )}

Cancel the common factor:

b^{2} - b - 12

= \frac{9}{b - 5}

4^{- 2^{- 1}}

43 - 627

(- 3)^{9}

cos^{2} (\frac{θ}{5}) - sin^{2} (\frac{θ}{5})

\frac{4.1 \cdot 1 0 ^{- 3}}{8.6 \cdot 1 0 ^{- 6}}

What is (9/(b^2-b-12))/(\frac{b-5){b^2-b-12}} ?
The solution to (9/(b^2-b-12))/(\frac{b-5){b^2-b-12}} is 9/(b-5)