What is (9/(b^2-b-12))/(\frac{b-5){b^2-b-12}} ?

The solution to (9/(b^2-b-12))/(\frac{b-5){b^2-b-12}} is 9/(b-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (9/(b^2-b-12))/(\frac{b-5){b^2-b-12}}

simplify

\frac{\frac{9}{b ^{2} - b - 12}}{\frac{b - 5}{b ^{2} - b - 12}}

\frac{9}{b - 5}

Solution steps

\frac{\frac{9}{b ^{2} - b - 12}}{\frac{b - 5}{b ^{2} - b - 12}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{9 ( b ^{2} - b - 12 )}{( b ^{2} - b - 12 ) ( b - 5 )}

Cancel the common factor:

b^{2} - b - 12

= \frac{9}{b - 5}

4^{- 2^{- 1}}

x^{3} y^{2} - x y^{4}

43 - 627

(- 3)^{9}

cos^{2} (\frac{θ}{5}) - sin^{2} (\frac{θ}{5})

What is (9/(b^2-b-12))/(\frac{b-5){b^2-b-12}} ?
The solution to (9/(b^2-b-12))/(\frac{b-5){b^2-b-12}} is 9/(b-5)