What is -2+sqrt(9-5x)>= 6 ?

The solution to -2+sqrt(9-5x)>= 6 is x<=-11

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-2+sqrt(9-5x)>= 6

- 2 + 9 - 5 x \geq 6

x \leq - 11

Interval Notation

(- \infty, - 11]

Solution steps

- 2 + 9 - 5 x \geq 6

Move

2

to the right side

9 - 5 x \geq 8

Square both sides

(9 - 5 x)^{2} \geq 8^{2}

Simplify

9 - 5 x \geq 64

9 - 5 x \geq 64 : x \leq - 11

x \leq - 11

Find singularity points

Find non-negative values for radicals:

x \leq \frac{9}{5}

Combine the intervals

x \leq - 11 and x \leq \frac{9}{5}

Merge Overlapping Intervals

x \leq - 11

(8 - 6 i) (- 4 - 4 i)

x - 7 = 19 + x

\frac{7 x - 2}{4} = 3 x + 1

5 x + 130 = 8 x + 151

(729)^{\frac{2}{3}}