What is the answer to 3xlog_{10}(2)+xlog_{10}(5)=5log_{10}(5)-log_{10}(2) ?

The answer to 3xlog_{10}(2)+xlog_{10}(5)=5log_{10}(5)-log_{10}(2) is x=log_{40}(3125/2)

Solve for x: 3xlog_{10}(2)+xlog_{10}(5)=5log_{10}(5)-log_{10}(2)

The solution is x=log_{40}(3125/2)

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3 x lo g_{10} (2) + x lo g_{10} (5) = 5 lo g_{10} (5) - lo g_{10} (2)

x = lo g_{40} (\frac{3125}{2})

Decimal Notation

x = 1.99357 \dots

Solution steps

3 x lo g_{10} (2) + x lo g_{10} (5) = 5 lo g_{10} (5) - lo g_{10} (2)

Factor

3 x lo g_{10} (2) + x lo g_{10} (5) : (3 lo g_{10} (2) + lo g_{10} (5)) x

(3 lo g_{10} (2) + lo g_{10} (5)) x = 5 lo g_{10} (5) - lo g_{10} (2)

Divide both sides by

3 lo g_{10} (2) + lo g_{10} (5)

x = lo g_{40} (\frac{3125}{2})

- \frac{1}{2} (1)^{2}

\frac{π}{\frac{π}{4}}

∣ x - 7 ∣ \leq 8

- x (x + 5) (x - 2)^{2} (x + 4) \leq 0

w^{3} - 8

What is the answer to 3xlog_{10}(2)+xlog_{10}(5)=5log_{10}(5)-log_{10}(2) ?
The answer to 3xlog_{10}(2)+xlog_{10}(5)=5log_{10}(5)-log_{10}(2) is x=log_{40}(3125/2)
Solve for x: 3xlog_{10}(2)+xlog_{10}(5)=5log_{10}(5)-log_{10}(2)
The solution is x=log_{40}(3125/2)