What is (2x^5-3x^2+4)-(x^5+2x^2+7) ?

The solution to (2x^5-3x^2+4)-(x^5+2x^2+7) is x^5-5x^2-3

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simplify (2x^5-3x^2+4)-(x^5+2x^2+7)

simplify

(2 x^{5} - 3 x^{2} + 4) - (x^{5} + 2 x^{2} + 7)

x^{5} - 5 x^{2} - 3

Solution steps

(2 x^{5} - 3 x^{2} + 4) - (x^{5} + 2 x^{2} + 7)

Apply rule:

(a) = a

(2 x^{5} - 3 x^{2} + 4) = 2 x^{5} - 3 x^{2} + 4

= 2 x^{5} - 3 x^{2} + 4 - (x^{5} + 2 x^{2} + 7)

Apply the distributive law:

- (a + b) = - a - b

- (x^{5} + 2 x^{2} + 7) = - x^{5} - 2 x^{2} - 7

= 2 x^{5} - 3 x^{2} + 4 - x^{5} - 2 x^{2} - 7

Group like terms

= 2 x^{5} - x^{5} - 3 x^{2} - 2 x^{2} + 4 - 7

Add similar elements:

2 x^{5} - x^{5} = x^{5}

= x^{5} - 3 x^{2} - 2 x^{2} + 4 - 7

Add similar elements:

- 3 x^{2} - 2 x^{2} = - 5 x^{2}

= x^{5} - 5 x^{2} + 4 - 7

Subtract the numbers:

4 - 7 = - 3

= x^{5} - 5 x^{2} - 3

x^{3} - 4 x^{2} + 3

\frac{\frac{p - 8}{p ^{2} - 12 p + 32}}{\frac{1}{p - 10}}

- \frac{7}{4} - 2

\frac{5 \frac{1}{4} \cdot ( \frac{4}{3} ) ^{2}}{( \frac{7}{3} ) ^{2} + 2 \frac{1}{7}}

3 x^{2} 6 x - 1

What is (2x^5-3x^2+4)-(x^5+2x^2+7) ?
The solution to (2x^5-3x^2+4)-(x^5+2x^2+7) is x^5-5x^2-3