What is (8x^2)/(16x^4+144x^3) ?

The solution to (8x^2)/(16x^4+144x^3) is 1/(2x(x+9))

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simplify (8x^2)/(16x^4+144x^3)

simplify

\frac{8 x ^{2}}{16 x ^{4} + 144 x ^{3}}

\frac{1}{2 x ( x + 9 )}

Solution steps

\frac{8 x ^{2}}{16 x ^{4} + 144 x ^{3}}

Factor

16 x^{4} + 144 x^{3} : 16 x^{3} (x + 9)

= \frac{8 x ^{2}}{16 x ^{3} ( x + 9 )}

Factor the number:

16 = 8 \cdot 2

= \frac{8 x ^{2}}{8 \cdot 2 x ^{3} ( x + 9 )}

Cancel the common factor:

8

= \frac{x ^{2}}{2 x ^{3} ( x + 9 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{3} = x^{2} x

= \frac{x ^{2}}{2 x ^{2} x ( x + 9 )}

Cancel the common factor:

x^{2}

= \frac{1}{2 x ( x + 9 )}

2 + 2 + 2

(x^{2} y^{5})^{3}

(x + 3) (3 x^{2} - 4 x - 5)

80 r^{5} s

\frac{x - 2}{x ^{2} + 4 x - 12}

What is (8x^2)/(16x^4+144x^3) ?
The solution to (8x^2)/(16x^4+144x^3) is 1/(2x(x+9))