What is log_{5}(12)-log_{5}(20)-log_{5}(15) ?

The solution to log_{5}(12)-log_{5}(20)-log_{5}(15) is -2

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simplify log_{5}(12)-log_{5}(20)-log_{5}(15)

simplify

lo g_{5} (12) - lo g_{5} (20) - lo g_{5} (15)

- 2

Solution steps

lo g_{5} (12) - lo g_{5} (20) - lo g_{5} (15)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{5} (12) - lo g_{5} (20) = lo g_{5} (\frac{12}{20})

= lo g_{5} (\frac{12}{20}) - lo g_{5} (15)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{5} (\frac{12}{20}) - lo g_{5} (15) = lo g_{5} (\frac{\frac{12}{20}}{15})

= lo g_{5} (\frac{\frac{12}{20}}{15})

\frac{\frac{12}{20}}{15} = 5^{- 2}

= lo g_{5} (5^{- 2})

Apply log rule:

lo g_{a} (a^{b}) = b

= - 2

9 \cdot (- 1)

125 m^{3} - 8 n^{3}

\frac{( - 24 x ^{3} + 18 x + 6 )}{( 6 x + 3 )}

a \cdot 2 a

6 \cdot 30

What is log_{5}(12)-log_{5}(20)-log_{5}(15) ?
The solution to log_{5}(12)-log_{5}(20)-log_{5}(15) is -2