What is (a^2+2a-3)/(a^2+4a-5) ?

The solution to (a^2+2a-3)/(a^2+4a-5) is (a+3)/(a+5)

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simplify (a^2+2a-3)/(a^2+4a-5)

simplify

\frac{a ^{2} + 2 a - 3}{a ^{2} + 4 a - 5}

\frac{a + 3}{a + 5}

Solution steps

\frac{a ^{2} + 2 a - 3}{a ^{2} + 4 a - 5}

Factor

a^{2} + 2 a - 3 : (a - 1) (a + 3)

= \frac{( a - 1 ) ( a + 3 )}{a ^{2} + 4 a - 5}

Factor

a^{2} + 4 a - 5 : (a - 1) (a + 5)

= \frac{( a - 1 ) ( a + 3 )}{( a - 1 ) ( a + 5 )}

Cancel the common factor:

a - 1

= \frac{a + 3}{a + 5}

\frac{- cos ( x )}{sin ( x )}

6 x (\frac{1}{6} - π) - x

ln (\frac{( x - 4 ) ^{2}}{x ^{2} - 1})^{\frac{2}{3}}

9 (3 - 4)^{2} + (\frac{1 - 1}{2})^{2}

(- 5) (- 4)

What is (a^2+2a-3)/(a^2+4a-5) ?
The solution to (a^2+2a-3)/(a^2+4a-5) is (a+3)/(a+5)