What is (4x^2-1)/(2x^2-x-1) ?

The solution to (4x^2-1)/(2x^2-x-1) is (2x-1)/(x-1)

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simplify (4x^2-1)/(2x^2-x-1)

simplify

\frac{4 x ^{2} - 1}{2 x ^{2} - x - 1}

\frac{2 x - 1}{x - 1}

Solution steps

\frac{4 x ^{2} - 1}{2 x ^{2} - x - 1}

Factor

4 x^{2} - 1 : (2 x + 1) (2 x - 1)

= \frac{( 2 x + 1 ) ( 2 x - 1 )}{2 x ^{2} - x - 1}

Factor

2 x^{2} - x - 1 : (2 x + 1) (x - 1)

= \frac{( 2 x + 1 ) ( 2 x - 1 )}{( 2 x + 1 ) ( x - 1 )}

Cancel the common factor:

2 x + 1

= \frac{2 x - 1}{x - 1}

\frac{3}{2} \cdot 0

(1 + cos (2 x))^{2}

4 (x^{2} - 3 x + 5) - 3 (x^{2} - 2 x + 1)

(6 i) (i)

What is (4x^2-1)/(2x^2-x-1) ?
The solution to (4x^2-1)/(2x^2-x-1) is (2x-1)/(x-1)