What is (2^2)/(3^4)\div (6^2)/(2^3) ?

The solution to (2^2)/(3^4)\div (6^2)/(2^3) is 8/729

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(2^2)/(3^4)\div (6^2)/(2^3)

\frac{2 ^{2}}{3 ^{4}} \div \frac{6 ^{2}}{2 ^{3}}

\frac{8}{729}

Solution steps

\frac{2 ^{2}}{3 ^{4}} \div \frac{6 ^{2}}{2 ^{3}}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{2 ^{2}}{3 ^{4}} \times \frac{2 ^{3}}{6 ^{2}}

\frac{2 ^{3}}{6 ^{2}} = \frac{2}{3 ^{2}}

= \frac{2}{3 ^{2}} \times \frac{2 ^{2}}{3 ^{4}}

Multiply fractions:

\frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d}

= \frac{2 ^{2} \times 2}{3 ^{4} \times 3 ^{2}}

2^{2} \times 2 = 2^{3}

= \frac{2 ^{3}}{3 ^{4} \times 3 ^{2}}

3^{4} \times 3^{2} = 3^{6}

= \frac{2 ^{3}}{3 ^{6}}

2^{3} = 8

= \frac{8}{3 ^{6}}

3^{6} = 729

= \frac{8}{729}

0.5 x - 2.5 y + 0.4 x - \frac{1}{2} y - \frac{2}{5} x

\frac{1}{x - 2} + \frac{2}{x + 2}

3 f (x)

3 \cdot 1 0^{7}

What is (2^2)/(3^4)\div (6^2)/(2^3) ?
The solution to (2^2)/(3^4)\div (6^2)/(2^3) is 8/729