What is (-24a^2b^2c^2-16abc)/(-12ab^2) ?

The solution to (-24a^2b^2c^2-16abc)/(-12ab^2) is (2c(3abc+2))/(3b)

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simplify (-24a^2b^2c^2-16abc)/(-12ab^2)

simplify

\frac{- 24 a ^{2} b ^{2} c ^{2} - 16 ab c}{- 12 a b ^{2}}

\frac{2 c ( 3 ab c + 2 )}{3 b}

Solution steps

\frac{- 24 a ^{2} b ^{2} c ^{2} - 16 ab c}{- 12 a b ^{2}}

Factor

- 24 a^{2} b^{2} c^{2} - 16 ab c : - (24 a^{2} b^{2} c^{2} + 16 ab c)

= \frac{- ( 24 a ^{2} b ^{2} c ^{2} + 16 ab c )}{- 12 a b ^{2}}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{24 a ^{2} b ^{2} c ^{2} + 16 ab c}{12 a b ^{2}}

Factor out common term

8 ab c : 8 ab c (3 ab c + 2)

= \frac{8 ab c ( 3 ab c + 2 )}{12 a b ^{2}}

Cancel the common factor:

a

= \frac{8 b c ( 3 ab c + 2 )}{12 b ^{2}}

Factor the number:

8 = 4 \cdot 2

= \frac{4 \cdot 2 b c ( 3 ab c + 2 )}{12 b ^{2}}

Factor the number:

12 = 4 \cdot 3

= \frac{4 \cdot 2 b c ( 3 ab c + 2 )}{4 \cdot 3 b ^{2}}

Cancel the common factor:

4

= \frac{2 b c ( 3 ab c + 2 )}{3 b ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

b^{2} = bb

= \frac{2 b c ( 3 ab c + 2 )}{3 bb}

Cancel the common factor:

b

= \frac{2 c ( 3 ab c + 2 )}{3 b}

(x + 3 y - 4)^{2}

lo g_{10} (5) (125)

\frac{3}{4} + \frac{7}{10}

2 lo g_{3} (9)

4 x^{2} - 12 x - 160

What is (-24a^2b^2c^2-16abc)/(-12ab^2) ?
The solution to (-24a^2b^2c^2-16abc)/(-12ab^2) is (2c(3abc+2))/(3b)