What is (m^2-m-4)+(m-5) ?

The solution to (m^2-m-4)+(m-5) is m^2-9

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simplify (m^2-m-4)+(m-5)

simplify

(m^{2} - m - 4) + (m - 5)

m^{2} - 9

Solution steps

(m^{2} - m - 4) + (m - 5)

Simplify

(m^{2} - m - 4) + (m - 5) : m^{2} - m - 4 + m - 5

= m^{2} - m - 4 + m - 5

Group like terms

= m^{2} - m + m - 4 - 5

Add similar elements:

- m + m = 0

= m^{2} - 4 - 5

Subtract the numbers:

- 4 - 5 = - 9

= m^{2} - 9

e^{\frac{1}{2} l n (y)}

(6 f^{2} - 9 f + 10) - (- 2 f^{2} - f + 3)

5!!

60!

\frac{2}{9} \cdot \frac{9}{10} + \frac{2}{3}