What is ((-4x^4+10x^3-26x^2+26x+6))/((-4x+6)) ?

The solution to ((-4x^4+10x^3-26x^2+26x+6))/((-4x+6)) is x^3-x^2+5x+1

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simplify ((-4x^4+10x^3-26x^2+26x+6))/((-4x+6))

simplify

\frac{( - 4 x ^{4} + 10 x ^{3} - 26 x ^{2} + 26 x + 6 )}{( - 4 x + 6 )}

x^{3} - x^{2} + 5 x + 1

Solution steps

\frac{- 4 x ^{4} + 10 x ^{3} - 26 x ^{2} + 26 x + 6}{- 4 x + 6}

Factor

- 4 x^{4} + 10 x^{3} - 26 x^{2} + 26 x + 6 : - 2 (2 x - 3) (x^{3} - x^{2} + 5 x + 1)

= \frac{- 2 ( 2 x - 3 ) ( x ^{3} - x ^{2} + 5 x + 1 )}{- 4 x + 6}

Factor

- 4 x + 6 : 2 (- 2 x + 3)

= \frac{- 2 ( 2 x - 3 ) ( x ^{3} - x ^{2} + 5 x + 1 )}{2 ( - 2 x + 3 )}

Cancel the common factor:

2

= \frac{- ( 2 x - 3 ) ( x ^{3} - x ^{2} + 5 x + 1 )}{- 2 x + 3}

Factor

- 2 x + 3 : - (2 x - 3)

= \frac{- ( 2 x - 3 ) ( x ^{3} - x ^{2} + 5 x + 1 )}{- ( 2 x - 3 )}

Cancel the common factor:

2 x - 3

= \frac{- ( x ^{3} - x ^{2} + 5 x + 1 )}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{x ^{3} - x ^{2} + 5 x + 1}{1}

Apply the fraction rule:

\frac{a}{1} = a

= x^{3} - x^{2} + 5 x + 1

(2 x - 3 y)^{2}

(1 - sin^{2} (x))^{3}

(y^{2} - 1)^{2}

cos (x) cot (x) + sin (x)

(cosh (x) - sinh (x))^{2}

What is ((-4x^4+10x^3-26x^2+26x+6))/((-4x+6)) ?
The solution to ((-4x^4+10x^3-26x^2+26x+6))/((-4x+6)) is x^3-x^2+5x+1